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x^2-90x=3600
We move all terms to the left:
x^2-90x-(3600)=0
a = 1; b = -90; c = -3600;
Δ = b2-4ac
Δ = -902-4·1·(-3600)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-150}{2*1}=\frac{-60}{2} =-30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+150}{2*1}=\frac{240}{2} =120 $
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